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TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-08-31
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A lax monoidal functor carries monoid objects to monoid objects

Statement

Let F:C→D be a lax monoidal functor. If (M,μ,η) is a monoid object in C, then F(M) is a monoid object in D with multiplication

F(M)⊠F(M)→F2;M,MF(M⊗M)→F(μ)F(M)

and unit

1′→F0F(1)→F(η)F(M).

Facts & Assumptions

Given: A lax monoidal functor F:C→D and a monoid object (M,μ,η) in C.

[L1]

A lax monoidal functor has structure maps F2 and F0 satisfying associativity and unit compatibility (Lax, strong, and strict monoidal functors).

[L2]

A monoid object is defined by multiplication and unit maps satisfying associativity and unit diagrams (Monoid objects and comonoid objects in a monoidal category).

Proof

technique · direct
1.1givenL1L2construct

Define μ′:=F(μ)∘F2;M,M and η′:=F(η)∘F0. These are the only typed maps with the displayed source and target.

2.1step 1.1L1L2

For associativity, paste the lax associativity square for F with the image under F of the monoid-object associativity square for μ. Both composites from (F(M)⊠F(M))⊠F(M) to F(M) equal F(μ∘(1M⊗μ)∘αM,M,M) with the same inserted F2-maps. Hence μ′ is associative.

2.2step 1.1L1L2

The left and right unit diagrams for η′ are obtained in the same way by pasting the lax unit squares with the image under F of the two unit diagrams for (M,μ,η). Thus η′ is a two-sided unit for μ′.

3.1step 2.1step 2.2L2∎

Therefore (F(M),μ′,η′) is a monoid object in D.

Depends on

Used by

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Dependency tree · two levels

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Sources