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The arbitrary compact product theorem is equivalent to AC
Statement
Over , AC (The Axiom of Choice) is equivalent to the assertion that every product of arbitrary compact spaces (Open cover, subcover, and compact topological space; a compact subset is a subspace that is compact in its own right, The product set of functions choosing a point in each factor, the projections, the box topology, and the product topology as the initial topology of the projections; the empty product is a one-point space) is compact. The empty product is a one-point space and is included.
Facts & Assumptions
Given: AC and, in the reverse direction, the hypothesis that every product of compact spaces is compact.
Under AC, Tychonoff's theorem gives compactness of every product of compact spaces, the empty product being the one-point space (Tychonoff's theorem: an arbitrary product of compact spaces is compact in the product topology, assuming the Axiom of Choice, The product set of functions choosing a point in each factor, the projections, the box topology, and the product topology as the initial topology of the projections; the empty product is a one-point space).
Over ZF, AC is equivalent to compactness of every product of compact spaces (The compact T1 product theorem is equivalent to AC, (Kolmogorov) and (Frechet) spaces).
Over ZF, BPI is equivalent to compactness of every product of compact Hausdorff spaces (Compact Hausdorff Tychonoff is equivalent to BPI).
Proof
Under AC every product of compact spaces is compact by [F1], and the empty product is the one-point space; this is one direction.
Conversely, if every product of compact spaces is compact then in particular every product of compact spaces is compact, since compact spaces are compact spaces; by [F2] this gives AC.
The two directions give the displayed equivalence; in particular the compact-Hausdorff case is a different statement, whose strength is BPI by [F3] and which is not identified with the arbitrary compact case here.
Remarks
- Why the two strengths differ. Products of compact spaces and products of compact Hausdorff spaces are not the same assertion: the first is equivalent to AC by [F2] and the second to BPI by [F3]. The empty product is compact in both cases and therefore separates nothing.
Depends on
- The compact T1 product theorem is equivalent to AC
- Compact Hausdorff Tychonoff is equivalent to BPI
- The Axiom of Choice
- The product set $\prod_{i \in I} X_i$ of functions choosing a point in each factor, the projections, the box topology, and the product topology as the initial topology of the projections; the empty product is a one-point space
- Open cover, subcover, and compact topological space; a compact subset is a subspace that is compact in its own right
- Tychonoff's theorem: an arbitrary product of compact spaces is compact in the product topology, assuming the Axiom of Choice
- $T_0$ (Kolmogorov) and $T_1$ (Frechet) spaces
Used by
Dependency tree · two levels
28 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Kyriakos Keremedis and Eleftherios Tachtsis, Wallman Compactifications and Tychonoff's Compactness Theorem in ZF (standard reference, not scraped)