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TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-13
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The asymmetric Lovász Local Lemma for finitely many events

Statement

Let D be a dependency digraph for finite events (Ai)iI. If there are reals 0xi<1 such that P(Ai)xijND+(i)(1xj) for every i, then P ⁣(iIAic)iI(1xi)>0.

Facts & Assumptions

Given: Events, a dependency digraph, and parameters satisfying the Statement.

[L1]

Under these hypotheses, conditioning Ai on any positive-probability intersection of other event complements gives probability at most xi (The conditional-probability induction underlying the Lovász Local Lemma).

[L2]

The finite chain rule factors the probability of an intersection through successive positive conditional probabilities (The multiplication rule and finite chain rule for conditional probability).

[L3]

Multiplication by a positive real preserves inequalities (Sign rules for products and monotonicity of multiplication).

Proof

technique · induction
1.1

For an empty event family, the intersection is the whole space and both empty products equal 1.

base
1.2

Order a nonempty family as i1,,im and assume the first r1 complements have intersection probability at least q<r(1xiq)>0.

ihchoose
2.1

By [L1], the conditional probability of Air given those complements is at most xir, so the conditional probability of Airc is at least 1xir>0.

step 1.2L1
3.1

Multiplying by the positive prefix probability gives P(qrAiqc)qr(1xiq)>0.

step 1.2step 2.1L2L3algebra
4.1

Induction through r=m proves both the lower bound and positivity.

step 1.1step 3.1discharge-induction

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 12 results over 4 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources