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Brauer-Nesbitt determines semisimplifications
Statement
Let and be finite-dimensional -modules over a splitting field of characteristic . Then
if and only if the semisimplifications and are isomorphic.
Facts & Assumptions
Given: Finite-dimensional -modules and .
Brauer characters are additive on short exact sequences (Brauer characters are additive on short exact sequences).
The irreducible Brauer characters form a basis of the complex vector space of class functions on (Irreducible Brauer characters form a basis of the p-regular class functions).
Proof
Repeatedly applying [L1] along a composition series of shows that is the sum of the irreducible Brauer characters of the composition factors of , counted with multiplicity. The same holds for .
If , then and have the same irreducible composition factors with the same multiplicities. Step 1.1 then gives .
Conversely, suppose . Subtracting the two expansions from step 1.1 gives a linear relation among irreducible Brauer characters. By [L2], those characters are linearly independent, so every coefficient is . Hence the composition multiplicities in and agree, and therefore .
Steps 2.1 and 2.2 prove the equivalence.
Depends on
Used by
Dependency tree · two levels
8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- J. Miquel Martinez, Modular Representation Theory of Finite Groups (standard reference, not scraped)
- Tudor Ciurca, Representation Theory (standard reference, not scraped)