Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-13
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For the linear-first convention, a basis change by P sends a sesquilinear matrix A to PTAσ(P); Hermitian forms satisfy A=σ(A)T

Statement

Let H be sesquilinear over a field with involution σ, using the convention linear in the first variable. If its old matrix is A and a basis change has matrix P, then its new matrix is

PTAσ(P),

where σ(P) is obtained entrywise. Moreover, H is Hermitian if and only if A=σ(A)T.

Facts & Assumptions

Given: A field involution σ, a sesquilinear form H, and the displayed basis data.

[L1]

Sesquilinearity is linear in the first variable and σ-linear in the second; Hermitian symmetry is H(u,v)=σ(H(v,u)) (Sesquilinear and Hermitian forms over a field with an involution, using the convention linear in the first variable).

[L2]

Matrix multiplication expands as the corresponding finite row-column sums (Matrix multiplication is associative, unital, distributive, and compatible with scalar multiplication).

Proof

technique · coordinate calculation
1.1

If x,y are new coordinate columns, their old columns are Px,Py. Expanding [L1] in an old basis gives H(u,v)=(Px)TAσ(Py)=xTPTAσ(P)σ(y).

L1L2L3algebra
1.2

In a basis (ei), Hermitian symmetry is Aij=H(ei,ej)=σ(H(ej,ei))=σ(Aji) for every i,j, which is exactly A=σ(A)T.

L1algebra
2.1

Since step 1.1 holds for every x,y, the new matrix is PTAσ(P). This includes the identity involution, where it reduces to ordinary congruence.

step 1.1
2.2

Conversely, if A=σ(A)T, the coordinate formula and σ2=id give H(u,v)=σ(H(v,u)) for arbitrary coordinate columns, so H is Hermitian.

step 1.2L1L2L3algebra
3.1

Steps 2.1, 1.2, and 2.2 prove the basis-change formula and both directions of the Hermitian criterion.

step 2.1step 1.2step 2.2

Depends on

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