Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
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Clifford restriction formula

Statement

Let G be finite, NG, θIrr(N), and χIrr(Gθ). Put I=IG(θ). There is a positive integer e such that ResNGχ=egIG/Igθ,χ(1)=e[G:I]θ(1). Here G/I indexes left cosets, one for each distinct conjugate. In particular, the entire restriction is isotypical precisely when I=G; it need not be isotypical in general.

Facts & Assumptions

Given: The groups, modules, characters, and hypotheses in the statement. All representations here are finite-dimensional complex left representations.

[F1]

An irreducible complex module restricts to one orbit of normal types with equal positive multiplicities. (Normal restriction has one orbit of constituents).

[F2]

For finite-dimensional complex representations of a finite group, the character of a direct sum is the sum of the characters. (Characters add on direct sums, multiply on tensor products, and conjugate on duals).

Proof

technique · direct
1.1

Let V afford χ. Its restriction is a direct sum with one common positive multiplicity e for the orbit of θ. The map gIgθ is well defined and bijective: two conjugates agree exactly when the corresponding elements differ on the right by an element of the stabilizer. Additivity of trace now gives the restriction formula.

F1F2given
2.1

At the identity every conjugate takes value θ(1), giving the degree formula. Since e>0, precisely [G:I] types occur. Thus an isotypical restriction forces [G:I]=1, hence I=G; conversely I=G makes the sum a single type. The calculation includes index one and both N=1 and N=G.

step 1.1algebra

Depends on

Used by

Dependency tree · two levels

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Sources