Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-09-12
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Regular languages are closed under inverse homomorphism

Statement

Let h:ΣΔ be an alphabet map with induced word map h^:ΣΔ. If KΔ is regular, then h^1(K):={wΣ:h^(w)K} is regular over Σ.

Facts & Assumptions

Given: An alphabet map h:ΣΔ and a regular language KΔ.

[L1]

By Alphabet maps into Δ and their induced maps on words, the induced map h^ is obtained by concatenating the image words of the letters of the input word.

[L2]

By The extended transition function of a DFA, a DFA transition function extends from letters to words, and the extension respects the recursive clause δ(q,ua)=δ(δ(q,u),a).

[L3]

By Acceptance of a word by a DFA and the recognized language, a word is accepted exactly when the extended transition from the start state lands in an accepting state.

[L4]

By Regular languages, every regular language is recognized by some DFA.

Proof

technique · direct
1.1

Choose a DFA D=(Q,Δ,δ,q0,F) with L(D)=K by [L4]. Define a DFA Dh over Σ with the same state set, start state, and accepting set by δh(q,a):=δ(q,h(a)) for each qQ and aΣ.

L2L4givenconstruct
2.1

We claim that for every word wΣ one has δh(q0,w)=δ(q0,h^(w)). The proof is by induction on w: for w=ε both sides equal q0, and appending one letter a updates the left-hand side by δh(,a) and the right-hand side by the block h(a), exactly as [L1] and [L2] prescribe.

L1L2step 1.1induction
3.1

By [L3] and step 2.1, the DFA Dh accepts w exactly when D accepts h^(w), that is, exactly when h^(w)K. Thus L(Dh)=h^1(K), so the inverse image is regular.

L3step 2.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources