Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A complex power-series sum re-expands about every interior point, at least to the distance from that point to the original boundary

Statement

If f(z)=n0cn(za)n has radius R and ba<R, then f(b+h)=k0f(k)(b)k!hkwhenever h<Rba. The displayed bound is a guaranteed radius, not necessarily the exact radius of the new series.

Facts & Assumptions

Given: A complex power-series sum f and an interior point b.

[L1]

Under ba+h<R, the binomial double series is absolutely convergent and may be regrouped (The binomial double series for re-expanding a complex power series is absolutely convergent and may be regrouped).

Proof

technique · direct
1.1

Put z=b+h. The binomial expansion and [L1] give f(b+h)=k0dkhk, where dk=nk(nk)cn(ba)nk.

L1algebra
2.1

By [L3], evaluating the kth derivative at b gives f(k)(b)=k!dk.

step 1.1L3
3.1

By [L2], dk=f(k)(b)/k!, proving the stated expansion for h<Rba. The bound remains valid when R=+.

step 1.1step 2.1L2

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 40 results over 11 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources