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Conditional bootstrap delta method for Hadamard differentiable maps
Statement
Let be separable Banach spaces, a closed linear subspace, , and a neighbourhood of . Let decrease to zero, let be data-measurable and tight, and let be bootstrap random elements such that and lie in with probability tending to one. Supply weak-convergence metrics on probability laws on and as in Conditional weak convergence in probability, with measurable distances for the conditional laws below. Assume:
- converges conditionally weakly in probability to the fixed law of , as in Conditional weak convergence in probability;
- is conditionally tight in probability: for each , there is a deterministic compact such that ;
- is Borel and is Borel measurable and Hadamard differentiable at , tangentially to , with continuous linear derivative as in Hadamard differentiability tangentially to a subspace.
Then
converges conditionally weakly in probability to the law of . Define the displayed bootstrap difference to be whenever either argument lies outside ; the assumed vanishing probability of this event makes this convention asymptotically immaterial.
Facts & Assumptions
Given: The spaces, sequences, conditional convergence, conditional tightness, domain and differentiability assumptions in the Statement.
Hadamard differentiability tangentially to a subspace: Along every and , the difference quotient converges to , where is continuous and linear.
Conditional weak convergence in probability: Conditional weak convergence means that a metric generating weak convergence between the conditional bootstrap law and the fixed limiting law tends to zero in probability.
Portmanteau theorem: Weak convergence of Borel probabilities is equivalent to the closed-set upper bound for every closed set .
Continuous mapping theorem: If and a measurable map is continuous -almost everywhere, then the image laws satisfy .
Subsequence characterization of convergence in probability: A scalar sequence tends to zero in probability exactly when every subsequence has a further subsequence tending to zero almost surely.
Proof
Given: The hypotheses and facts in the Statement and Facts & Assumptions.
For every compact , . If this failed, some subsequence would have with the displayed norm bounded below by a positive constant. Compactness gives a further subsequence ; [F1] applied to that subsequence makes the norm tend to zero, a contradiction.
Write for the bootstrap difference with the stated convention, and . Fix . Tightness gives a compact with ; conditional tightness gives compact with . Because is a neighbourhood of , the arguments associated to the bounded compact sets and lie in for all sufficiently large . Step 1.1 on these two compact sets and linearity show uniformly there that . Since is fixed under conditioning, eventually. Thus the limit superior of is at most . Letting proves in probability for every .
Start with any subsequence. The nonnegative scalar tends to zero in probability: truncate the sum, use step 2.1 for its finitely many terms, and bound the tail by its geometric sum. By [F5], extract a further subsequence along which this scalar tends to zero almost surely, so the input metric distance and every remainder probability do also. Fix an outcome in their common probability-one event. The continuous mapping theorem [F4] gives weak convergence of the conditional laws of . For every closed and , , where is closed. Apply [F3] and let ; continuity from above of the fixed limiting probability gives the closed-set bound for . Thus [F3] gives weak convergence on this outcome, hence convergence to zero of the supplied output weak-metric distance. A final application of [F5] proves convergence of that distance in probability along the full sequence.
Remarks
This theorem is conditional on the bootstrap limit and tightness hypotheses. It does not prove those hypotheses for a particular resampling algorithm.
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