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Sufficiency makes the conditional rejection probability nuisance-free

Statement

Let (X,A) and (S,S) be standard Borel spaces as in Standard Borel spaces. Fix Polish topologies realizing these specified Borel sigma-algebras, as the standard-Borel definition permits. Let Θ0,Θ1 be nonempty disjoint parameter subsets, and write {Pη:η∈Θ0} for the null subfamily. Let S:X→S be measurable. Suppose there is one probability kernel K(s,⋅) such that, for every η∈Θ0, K(S,⋅) is a regular conditional distribution of the full data X given σ(S) under Pη. This is the common-kernel premise of sufficiency for the null subfamily in Sufficient statistics. For any measurable φ:X→[0,1], define q(s):=∫Xφ(x)K(s,dx). Then q is measurable and q(S) is a version of the conditional rejection probability of φ given S under every Pη. The same function q works for every nuisance value, with conditional-expectation identities interpreted almost surely under each corresponding law.

Facts & Assumptions

Given: The spaces, null family, statistic, common probability kernel and bounded test function in the Statement.

[A1]

For every η∈Θ0, the same kernel K(S,⋅) satisfies the conditional event-integral identities for X given S under Pη, which is the common-kernel sufficiency condition in Sufficient statistics.

[F1]

A conditional law K(s,⋅) of a random element given S composes with S to give a regular conditional distribution given σ(S). Conditional law given a random element

[F2]

Integrating a product-measurable function against a probability kernel gives a measurable function of the kernel parameter. Measurability of integration against a kernel

[F3]

If K(S,⋅) is a supplied regular conditional distribution of X given σ(S), then ∫f(x)K(S,dx) satisfies the conditional event-integral identities for nonnegative measurable f; for integrable real f its signed integral is a conditional-expectation version. Conditional integration through a regular conditional law

[F4]

A conditional test's rejection probability given S is a conditional-expectation version of φ(X). Conditional tests given a statistic

[F5]

The product sigma-algebra is generated by rectangles, so the second-coordinate projection is measurable; composing it with measurable φ makes (s,x)↦φ(x) product-measurable. The product sigma-algebra and its finite iterates, Composition with a Borel measurable outer map preserves measurability

Proof

1.1F2F5given

The map (s,x)↦φ(x) is product-measurable by [F5]. Kernel integration [F2] therefore makes q measurable. Since K(s,⋅) is a probability measure and 0≤φ≤1, every value satisfies 0≤q(s)≤1.

2.1A1F1F3F4step 1.1∎

Fix η∈Θ0. By [A1] and [F1], K(S,⋅) is a regular conditional distribution of X given σ(S) under Pη. Applying [F3] to the bounded function φ shows that for every A∈σ(S), ∫Aq(S) dPη=∫Aφ(X) dPη. Thus q(S) is a version of the conditional rejection probability under this null law. The same kernel in [A1] defines the same q for every η, proving nuisance-freeness; only the individual laws' almost-sure qualifications are used.

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