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TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-08-30
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Continuity from below, and from above when one set has finite signed measure

Statement

Let ν be a signed measure on (X,A).

  1. If E0E1 are measurable and E=nEn, then ν(E)=limnν(En).
  2. If E0E1 are measurable, E=nEn, and ν(En0)R for some n0, then ν(E)=limnν(En).

Facts & Assumptions

Given: A signed measure ν on (X,A).

[L1]

Jordan decomposition gives positive measures ν+,ν with ν=ν+ν. (Jordan decomposition of a signed measure into unique mutually singular positive parts)

[L2]

Measures are continuous from below on increasing measurable sequences. (Continuity from below for measures)

[L3]

Measures are continuous from above on decreasing measurable sequences once one term has finite measure. (Continuity from above when one set has finite measure)

[L4]

Every measurable subset of a finite signed-measure set has finite signed measure. (A subset of a set of finite signed measure also has finite signed measure)

Proof

technique · direct
1.1

Let EnE. By [L1], write ν=ν+ν. Then [L2] gives ν+(E)=limnν+(En),ν(E)=limnν(En). Subtracting these two equalities yields ν(E)=ν+(E)ν(E)=limn(ν+(En)ν(En))=limnν(En).

1.2

Let EnE and assume ν(En0)R for some n0. Choose a Hahn decomposition X=PN from [L1]. Because En0P and En0N are measurable subsets of the finite signed-measure set En0, [L4] shows that both ν(En0P)=ν+(En0) and ν(En0N)=ν(En0) are finite. Hence [L3] gives ν+(E)=limnν+(En),ν(E)=limnν(En). Subtracting again yields ν(E)=limnν(En).

L1L3L4
2.1

The displayed subtractions are defined because for a signed measure at most one of ν+(E) and ν(E) can be infinite, and the same holds for each En.

L1step 1.1
3.1

Steps 1.1 through 2.1 prove continuity from below and from above under the stated finiteness hypothesis.

step 1.1step 1.2step 2.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources