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TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-28
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Locally uniform convergence preserves the total multiplicity near an isolated zero

Statement

Let ΩC be open, let fn:ΩC be holomorphic, and suppose fnf locally uniformly on Ω. Let aΩ be an isolated zero of f of multiplicity m1. Then there is r>0 such that D(a,r)Ω, the function f has no zero on za=r, and for all sufficiently large n the function fn has exactly m zeros in D(a,r) counted with multiplicity.

Facts & Assumptions

Given: Holomorphic functions fn on an open set Ω converging locally uniformly to f, and an isolated zero a of f of multiplicity m.

[L1]

A strict boundary perturbation preserves the total zero multiplicity in the disc (Small perturbations preserve the total local zero multiplicity).

Proof

technique · direct
1.1

By the isolated-zero hypothesis, choose r>0 with D(a,r)Ω such that a is the only zero of f in D(a,r). Then f is a positive continuous function on the circle za=r, so it has a positive minimum there. Call that minimum η.

given
2.1

Because fnf locally uniformly and the circle za=r is compact, there is N such that fn(z)f(z)<ηf(z)(za=r, nN). Applying [L1] on that circle shows that for every nN, the function fn has the same total zero multiplicity in D(a,r) as f, namely m.

step 1.1L1
3.1

Step 2.1 is exactly the claimed persistence of the local multiplicity.

step 2.1

Depends on

Used by

Dependency tree · two levels

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Sources