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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-28
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Continuity principle for domains of holomorphy

Statement

Let Ω⊆Cm be a domain of holomorphy, and let Φ:[0,1]×D‾→Cm be a continuous family of analytic discs. Assume that there is a compact set K⋐Ω with Φt(∂D)⊆K for every t, and that Φ0(D‾)⋐Ω. Then

Φt(D‾)⊆Ω(t∈[0,1]).

Facts & Assumptions

Given: A domain of holomorphy Ω and a continuous family of analytic discs Φ satisfying the boundary and initial-disc hypotheses.

[L1]

The family and its boundary hypotheses are those of Continuous families of analytic discs.

[L2]

A domain of holomorphy is holomorphically convex, so the holomorphic hull of a compact subset is compactly contained in the domain (Cartan-Thullen theorem).

[L3]

A function holomorphic on a disc and continuous on its closure is bounded there by its boundary maximum (Boundary maximum modulus principle on a bounded domain).

Proof

technique · direct
1.1L1L2given

Put H:=K^Ω. By [L2], H⋐Ω. Let S:={t∈[0,1]:Φt(D‾)⊆Ω}. The initial-disc hypothesis gives 0∈S. If t∈S, then the compact set Φt(D‾) lies in the open set Ω; uniform continuity of Φ on the compact parameter product shows that the same containment holds for all parameters sufficiently close to t. Thus S is open in [0,1].

2.1L1L3step 1.1

If t∈S and f∈O(Ω), then f∘Φt is holomorphic on D and continuous on its closure. By [L3] and the boundary hypothesis, ∣f(Φt(λ))∣≤sup⁡∂D∣f∘Φt∣≤sup⁡K∣f∣(λ∈D‾). Since this holds for every f, one has Φt(D‾)⊆H.

3.1step 1.1step 2.1L2∎

Let tn∈S and tn→t. For every λ∈D‾, step 2.1 gives Φtn(λ)∈H. The compact set H is closed in Cm, so continuity of Φ yields Φt(λ)∈H⊆Ω. Hence t∈S, and S is closed. Since [0,1] is connected and S is nonempty, open, and closed, S=[0,1].

Depends on

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Sources