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Countable factorization criterion for sufficiency
Statement
Let be a nonempty countable set with its full -field, let , let be a statistic into a standard Borel space, and write . Then is sufficient if and only if there are nonnegative functions and Borel such that
The pointwise convention is whenever , where on the countable image ; outside that image set .
Facts & Assumptions
Given: the countable experiment, the statistic , and the displayed factorization or a common kernel, according to the implication being proved.
Sufficient statistics: sufficiency means one probability kernel satisfying the conditional-law identity for every model law.
Measure kernel and probability kernel: for each target event, a probability kernel is measurable in its conditioning argument and is a probability measure in its event argument.
Standard Borel spaces: singletons in a standard Borel space are Borel, and countable subsets are Borel.
Proof
Suppose is sufficient and fix a common kernel from [F1]. For set and . The image is countable by countability of , hence Borel by [F3]; every function on this image extended by zero is Borel. Define and define when , and zero when . Then is Borel and nonnegative.
If , choose with . The conditional identity in [F1] gives and for every ; if , both sides vanish by the same identity. Thus . If , every law gives that fiber probability zero, so . This proves the forward implication pointwise.
Conversely suppose the factorization holds. For each let and . If some , then and , since the sum of the probabilities on the fiber is at most one. In that case put on and zero off . If all , choose the first point of in a fixed enumeration and let be its point mass. For choose one fixed and set . The countable image and enumeration make every coordinate Borel. For each , is a countable sum of Borel functions, so it is Borel; the point-mass assignments are countably additive probability measures.
On an active fiber, for every , . On an inactive fiber both sides are zero. Summing over the countably many gives the conditional-law identity for every Borel . Thus [F1] holds and is sufficient.
Depends on
Used by
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Dependency tree · two levels
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Sources
- Ryan Martin, Lecture Notes on Advanced Statistical Theory (standard reference, not scraped)
- Joshua M. Tebbs, STAT 512 Mathematical Statistics Lecture Notes (standard reference, not scraped)
- Peter Kempthorne, MIT 18.655 Lecture Note 6: Sufficiency (standard reference, not scraped)
- Noah Fithian, Stat 210a Reader: Sufficiency (standard reference, not scraped)
- Noah Fithian, Stat 210a Reader: Completeness, Ancillarity, and Basu’s Theorem (standard reference, not scraped)
- Charles J. Geyer, Stat 5421 Lecture Notes: Exponential Families (standard reference, not scraped)
- Jiahao Tian, Chapter 2: Sufficiency and Exponential Families (standard reference, not scraped)