Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-14
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Curvature two-form structure equation

Statement

Let e=(e1,,er) be a local frame, let ω=(ωij) be its connection matrix, and let Ω=(Ωij) be the matrix of the curvature two-form, defined by R(X,Y)ej=Ωij(X,Y)ei. Then

Ω=dω+ωω,

where multiplication order is fixed by

(ωω)ij=kωikωkj.

Facts & Assumptions

[F1]

Bundle curvature is an End(E)-valued two-form. Vector-bundle curvature is an endomorphism-valued two-form.

[F2]

In the supplied frame, Xej=ωij(X)ei. Connection one form in a local frame.

[F3]

For s=eu, Xs=e(Xu+ω(X)u). Local coordinate formula for a bundle connection.

[F4]

The exterior derivative of a local coordinate expansion differentiates its scalar coefficients. The local coordinate formula for the exterior derivative.

[F5]

The wedge product is the pointwise alternating product of forms. The wedge product of differential forms.

Proof

Given: A local frame e, a coordinate chart on its domain, and coordinate fields a,b.

1.1

Since coordinate fields commute, expand the defining curvature commutator on ej with [F2]–[F3]. The coefficient of ei is a(ωij(b))b(ωij(a))+k(ωik(a)ωkj(b)ωik(b)ωkj(a)).

F1F2F3algebra
2.1

By [F4], the first two terms in step 1.1 are dωij(a,b); by [F5], the sum is k(ωikωkj)(a,b) in precisely the stated matrix order. Both sides are two-forms by [F1], so equality on every coordinate-frame pair proves Ωij=dωij+kωikωkj.

F1F4F5step 1.1algebra

Depends on

Used by

Dependency tree · two levels

20 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources