Alphabeta Math
TheoremStatement: Literature-sourcedProof: Literature-sourcedaudited 2026-08-28
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The cycle index of the cyclic group C_n

Statement

Let Cn act on the vertices of a labelled n-gon by rotation, with n≥1. Then

Z(Cn)=1n∑d∣nφ(d) sdn/d.

Facts & Assumptions

Given: an integer n≥1 and the rotation action of Cn on the vertices of a labelled n-gon.

[A1]

A rotation by r steps sends each vertex i to i+r(modn).

[L1]

Proof

technique · direct
1.1A1algebra

A rotation by r steps decomposes the n vertices into gcd⁡(n,r) cycles, each of length n/gcd⁡(n,r). Therefore its cycle-index monomial is sn/gcd⁡(n,r)gcd⁡(n,r).

2.1step 1.1L1algebra

Fix a divisor d of n. A rotation contributes the monomial sdn/d exactly when its cycles have length d, equivalently when its step size has the form r=(n/d)a with a coprime to d. Indeed, the order of the rotation by r is the least positive m with mr≡0(modn), and for r=(n/d)a this least m is exactly d when gcd⁡(a,d)=1. Therefore the rotations of order d are in bijection with the units a∈(Z/d)×, so there are φ(d) of them by [L1].

3.1step 2.1∎

Average the monomials over all n rotations. Grouping them by the divisor d from step 2.1 yields Z(Cn)=1n∑d∣nφ(d) sdn/d.

Depends on

Used by

Dependency tree · two levels

13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources