Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The diagonal intersection of clubs is club

Statement

In ZFC, if κ is regular uncountable and (Cξ)ξ<κ is a sequence of clubs of κ, then D=ξ<κCξ is club.

Facts & Assumptions

[F1]

Diagonal intersection and union: Membership at alpha tests only indices xi<alpha.

[F2]

Closure points form a club: Any self-map of a regular uncountable cardinal has club many closure points.

Proof

Given: The objects and hypotheses in the statement.

1.1

Define g(β)=supξβmin(Cξ(β+1)). Regularity keeps this below κ. By the closure-point lemma, there are unboundedly many nonzero closure points α of g; these are limits since g(β)>β. Fix ξ<α and any η<α, then take β<α with βξ,η. The least Cξ point above β is below α. Thus αCξ, proving αD.

F1F2
2.1

If δ is a nonzero limit point of D, then for each ξ<δ the points of Dδ above ξ belong to Cξ and are unbounded in δ. Its closure gives δCξ for every ξ<δ, hence δD. This proves closure. Zero is in D by definition.

F1step 1.1

Depends on

Used by

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources