Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedaudited 2026-09-07
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Elementary initial segments form a club

Statement

In ZFC, if κ is regular uncountable and M has universe κ in a finitary language of size less than κ, then

EM={0<α<κ:Mα is an elementary substructure of M}

is club in κ.

Facts & Assumptions

[F1]

Skolem witness closure on a cardinal: Fewer than kappa finite-arity functions suffice for elementary restrictions; the existential witness criterion is proved there.

[F2]

Closure points form a club: Every self-map of kappa has club many closure points.

Proof

Given: The objects and hypotheses in the statement.

1.1

Use the witness family H. For β<κ, let g(β)=sup({h(a)+1:hH, a(β+1)arity(h)}{β+1}). There are fewer than kappa values: the finite-string cardinal count in the witness lemma bounds all tuples, and multiplying by H<κ still gives fewer than kappa. Regularity therefore gives g(β)<κ.

F1F3
2.1

The nonzero closure points alpha of g form an unbounded set. Since g(β)>β, such alpha are limits. Every finite tuple below alpha is contained in some β+1<α; hence every h value on it is below alpha. This includes the empty tuple for constants. The witness lemma gives αEM. Thus EM is unbounded.

F1F2step 1.1
3.1

If delta is a nonzero limit point of EM, every finite tuple below delta lies below some αEMδ. Language-function closure at alpha makes the restriction to delta a substructure. Any existential formula true in M with such a tuple has a witness below alpha by elementarity there, hence below delta. The witness criterion proves elementarity at delta. Thus EM itself is closed, completing the club claim.

F1step 2.1

Depends on

Used by

Dependency tree · two levels

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Sources