Alphabeta Math
TheoremStatement: Literature-sourcedProof: Literature-sourcedaudited 2026-08-28
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Euler's pentagonal number theorem by Franklin's involution

Statement

In Z⟦x⟧,

∏m≥1(1−xm)=∑r∈Z(−1)rxr(3r−1)/2.

Equivalently,

∏m≥1(1−xm)=1+∑r≥1(−1)r(xr(3r−1)/2+xr(3r+1)/2).

Facts & Assumptions

Given: for each n≥0, let qe(n) and qo(n) denote the numbers of partitions of n into an even, respectively odd, number of distinct parts.

[F1]

A partition into distinct parts is a finite strictly decreasing list of positive integers; qe(n) and qo(n) count the even-length and odd-length such partitions of n (The functions p(n), p_k(n), and the standard restricted partition families).

[F2]

Expanding ∏m≥1(1−xm) chooses each part size m either not at all or once, with sign −1 when it is chosen, so the coefficient of xn is qe(n)−qo(n).

Proof

technique · sign-reversing involution
1.1F1construct

Let λ=(λ1>⋯>λℓ) be a nonempty partition into distinct parts. Write s=λℓ for its smallest part, and let t be the largest index such that λi=λ1−i+1 for every 1≤i≤t. Thus the first t rows form the maximal upper-right staircase. If s≤t and λ≠(2s−1,2s−2,…,s), define α(λ) by deleting the last part s and adding 1 to each of the first s parts. If s>t and λ≠(2t,2t−1,…,t+1), define β(λ) by subtracting 1 from each of the first t parts and adjoining a new last part t.

2.1step 1.1algebra

In the first case of step 1.1, the partition α(λ) is still distinct: the first s parts remain strictly decreasing, the last changed part satisfies λs+1>λs+1 because those rows were consecutive, and deleting the old last part decreases the number of parts by 1. The first s parts of α(λ) are consecutive and its smallest part is larger than s, so α(λ) falls under the second construction with parameter t=s, and β(α(λ))=λ.

2.2step 1.1algebra

In the second case of step 1.1, the partition β(λ) is still distinct: maximality of t gives λt−1>λt+1, while the new last part t is smaller than the previous smallest part because s>t. The first t parts of β(λ) are consecutive and its smallest part is exactly t, so β(λ) falls under the first construction with parameter s=t, and α(β(λ))=λ. Thus steps 2.1 and 2.2 define a sign-reversing involution on all nonexceptional nonempty distinct partitions.

2.3step 1.1algebra

The empty partition contributes the constant term 1. The only nonempty distinct partitions excluded from step 1.1 are the two staircase families (2k−1,2k−2,…,k) and (2k,2k−1,…,k+1). Their sizes are k+(k+1)+⋯+(2k−1)=k(3k−1)/2 and (k+1)+(k+2)+⋯+2k=k(3k+1)/2, and each has exactly k parts, so each contributes the sign (−1)k.

3.1F2step 2.2step 2.3∎

By step 2.2, all nonexceptional nonempty distinct partitions cancel in opposite-parity pairs. Step 2.3 leaves only the empty partition and the two exceptional staircase families, so [F2] gives ∏m≥1(1−xm)=1+∑k≥1(−1)k(xk(3k−1)/2+xk(3k+1)/2), equivalently the two-sided sum over r∈Z.

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