Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-13
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Bayes' theorem over a finite partition

Statement

Let B0,…,Bn−1 be a finite partition with P(Bi)>0 for every i<n. If P(A)>0, then for every j<n, P(Bj∣A)=P(A∣Bj)P(Bj)∑i<nP(A∣Bi)P(Bi).

Facts & Assumptions

Given: A finite partition, an event A of positive probability, and an index j<n as in the Statement.

[L1]

The multiplication rule gives P(A∩B)=P(A∣B)P(B) whenever P(B)>0 (The multiplication rule and finite chain rule for conditional probability).

[L2]

The law of total probability gives P(A)=∑iP(A∣Bi)P(Bi) (The law of total probability for a finite partition).

Proof

technique · direct
1.1

By conditional probability and symmetry of intersection, P(Bj∣A)=P(A∩Bj)/P(A).

L1
2.1

The numerator in step 1.1 is P(A∣Bj)P(Bj), and [L2] is the denominator.

L1L2
3.1

Substitution yields the formula; its denominator is positive because it equals P(A)>0.

step 1.1step 2.1algebra∎

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources