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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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Flux is invariant under orientation-preserving reparametrization and changes sign under reversal

Statement

An orientation-preserving reparametrization preserves flux and an orientation-reversing reparametrization negates it.

Facts & Assumptions

Given: A regular reparametrization ψ=φ∘h between connected parameter regions and a continuous vector field F.

[L1]

Flux is the integral of F∘φ dotted with the oriented area vector, and that vector transforms by the signed factor det⁡Dh (Unit normal fields, orientations, and flux through a regular surface patch, The oriented area vector transforms by the parameter Jacobian determinant).

[L2]

The determinant has one constant sign on the parameter region (A regular reparametrization of a connected parameter region has a constant orientation sign), and compact-Jordan change of variables uses ∣det⁡Dh∣ (Change of variables for an injective C1 map on a compact Jordan set).

Proof

technique · cases
1.1givenL1

By [L1], flux computed with ψ is ∫E((F∘φ)⋅(φu×φv))∘h det⁡Dh.

2.1step 1.1L2

In the preserving case [assume-case pos], [L2] gives det⁡Dh=∣det⁡Dh∣, so change of variables makes step 1.1 equal to the flux computed with φ.

2.2step 1.1L2

In the reversing case [assume-case neg], [L2] gives det⁡Dh=−∣det⁡Dh∣, so change of variables makes step 1.1 the negative of the flux computed with φ.

3.1step 2.1step 2.2cases-exhaustive∎

The two constant-sign cases are exhaustive, proving both assertions.

Depends on

Used by

Dependency tree · two levels

26 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources