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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-sol)audited 2026-09-27
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Frobenius kernel theorem

Statement

Let G be a finite Frobenius group with complement H and let N=(G∖⋃x∈GxHx−1)∪{1} be the associated kernel set. Then N is a normal subgroup of G.

Facts & Assumptions

Given: A finite group G with Frobenius complement {1}<H<G and the kernel set N with its associated family I of nontrivial irreducible characters of H.

[F1]

N=⋂φ∈Iker⁡φ~ for a nonempty family {φ~:φ∈I} of irreducible complex characters of G (Frobenius kernel is an intersection of character kernels).

[F2]

If ρ is a finite-dimensional complex representation of G with character χ, then ker⁡χ=ker⁡ρ⊴G (The kernel of a complex character agrees with the kernel of any representation affording it).

[F3]

The intersection of a nonempty family of normal subgroups of G is again a normal subgroup of G (The intersection of a nonempty family of normal subgroups is normal).

Proof

technique · direct
1.1

By [F1], N is the intersection over the nonempty family of kernels ker⁡φ~ of irreducible characters φ~ of G.

F1given
2.1

Each ker⁡φ~ occurring in [F1] is a normal subgroup of G: it is the kernel of the representation ρ affording the character φ~, hence equals ker⁡ρ, which is normal by [F2].

F2step 1.1
3.1

Therefore N is an intersection of a nonempty family of normal subgroups of G, so by [F3] it is a subgroup of G and is normal in G. In particular the kernel set is closed under products and inverses, a fact that the counting argument of Frobenius kernel cardinality could not supply. ∎

F1F3step 1.1step 2.1

Depends on

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Dependency tree · two levels

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Sources