Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generatedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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H_kappa is a transitive subset of V_kappa

Statement

In ZF, for every infinite initial ordinal κ, Hκ is a transitive set and Hκ⊆Vκ. For infinite initial ordinals κ≤μ, one has Hκ⊆Hμ.

Facts & Assumptions

Given: Work in ZF unless the statement explicitly weakens or supplements it; fix the objects and hypotheses of the statement.

[F1]

In ZF, if a transitive set T injects into an ordinal λ<κ, where κ is an infinite initial ordinal, then rank⁡(t)<κ for every t∈T. No regularity or Choice is assumed. (A small transitive set bounds its ranks)

[F2]

In ZF, for every set x and ordinal α, x∈Vα  ⟺  rank⁡(x)<α,x⊆Vα  ⟺  rank⁡(x)≤α. Thus rank⁡(x) is the least α with x⊆Vα, and rank⁡(x)=α iff x∈Vα+1∖Vα. (Rank characterizes hierarchy membership)

Proof

1.1F1F2

For x∈Hκ, let T=TC⁡({x}) and use its witnessing injection into λ<κ. This is a transitive set containing x as an element, so the small-ranks lemma gives rank⁡(x)<κ. Rank characterization puts x∈Vκ. Separation inside Vκ now proves that Hκ is a set.

2.1F1step 1.1

If y∈x∈Hκ, the transitive set TC⁡({x}) contains y, and hence contains TC⁡({y}) by minimality. Restrict the same witnessing injection to this smaller closure. Thus y∈Hκ, proving transitivity.

3.1F1∎

If κ≤μ, any witnessing ordinal λ<κ also satisfies λ<μ. The same injection proves x∈Hμ.

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources