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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-09
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The inflation–restriction–transgression five-term sequence

Statement

Assume AC. For every group extension 1→N→G→Q→1 and left G-module A, the sequence 0⟶H1(Q,AN)→inf⁡H1(G,A)→res⁡H1(N,A)Q→Tra⁡H2(Q,AN)→inf⁡H2(G,A) is exact at every term having a following displayed arrow. Tra uses the normalizer quotient and its printed DHW cocycle sign; degree-two inflation includes coefficient inclusion. Cohomology is normalized bar cohomology, with its inherited derived interpretation. No exactness assertion at the last term is intended.

Facts & Assumptions

Given: AC, the extension and module A.

[F1]

Inflation is injective and its image is the kernel of restriction (Degree-one inflation–restriction is exact).

[F2]

The kernel of Tra is the restriction image (The kernel of transgression is the image of restriction).

[F3]

The kernel of degree-two inflation is the image of Tra (The kernel of degree-two inflation is the transgression image).

Proof

1.1F1F2given

Use the degree-one inflation and restriction formulas with coefficients AN⊆A. F1 gives injectivity of the first arrow and exactness at H1(G,A). Its codomain for restriction is precisely H1(N,A)Q, the domain of Tra in F2.

2.1F2F3step 1.1algebra∎

F2 gives exactness at H1(N,A)Q. F3 applies to the same normalizer transgression and the pullback/coefficient-inclusion inflation and gives exactness at H2(Q,AN). These cover every asserted location, including zero composites. No result about the cokernel of the final map is used or claimed. For N=1 the two inflation maps are identities and H1(N,A)=0; for Q=1 the restriction map is the identity and both positive-degree Q groups vanish, so the degenerate sequences agree.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources