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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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Invariant-factor decomposition of a finitely generated module over a PID

Statement

Every finitely generated PID module is a finite free module direct-summed with cyclic torsion quotients. Precisely, if M is finitely generated over a PID R, then

M≅Rs⊕R/(a1)⊕⋯⊕R/(at),

where each ai is a nonzero nonunit and a1∣⋯∣at. Every finitely generated PID module has an invariant-factor decomposition. This assertion is existence; uniqueness is proved separately.

Facts & Assumptions

Given: A finitely generated module M, quotient modules (Quotient module M/N with scalar multiplication on additive cosets), and the first isomorphism theorem for modules (First isomorphism theorem for modules: M/ker⁡f≅im⁡f).

[L1]

For a submodule N of a free PID module M of finite rank n, there are a basis e1,…,en of M and nonzero elements a1∣⋯∣ar with r≤n such that a1e1,…,arer is a basis of N (Simultaneous bases for a submodule of a finite free module over a PID).

Proof

technique · constructive
1.1givenconstruct

Choose generators m1,…,mn of M and define the surjection π:Rn→M by sending the standard basis to them; put N=ker⁡π. For the zero module one may take n=0.

2.1step 1.1L1

Apply [L1] to N≤Rn. There is a basis e1,…,en of Rn and a basis a1e1,…,arer of N, with nonzero a1∣⋯∣ar.

3.1step 2.1givenalgebradischarge-construct∎

The first isomorphism theorem and coordinatewise quotient give M≅Rn/N≅R/(a1)⊕⋯⊕R/(ar)⊕Rn−r. Any unit ai contributes the zero quotient and is removed; the remaining nonunit factors preserve the divisibility chain. This constructs the stated decomposition, including purely free, purely torsion, cyclic, and empty cases.

Depends on

Used by

Dependency tree · two levels

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Sources