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TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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Invariant-factor decomposition of a finitely generated module over a PID

Statement

Every finitely generated PID module is a finite free module direct-summed with cyclic torsion quotients. Precisely, if M is finitely generated over a PID R, then

MRsR/(a1)R/(at),

where each ai is a nonzero nonunit and a1at. Every finitely generated PID module has an invariant-factor decomposition. This assertion is existence; uniqueness is proved separately.

Facts & Assumptions

Given: A finitely generated module M, quotient modules (Quotient module M/N with scalar multiplication on additive cosets), and the first isomorphism theorem for modules (First isomorphism theorem for modules: M/kerfimf).

[L1]

For a submodule N of a free PID module M of finite rank n, there are a basis e1,,en of M and nonzero elements a1ar with rn such that a1e1,,arer is a basis of N (Simultaneous bases for a submodule of a finite free module over a PID).

Proof

technique · constructive
1.1

Choose generators m1,,mn of M and define the surjection π:RnM by sending the standard basis to them; put N=kerπ. For the zero module one may take n=0.

givenconstruct
2.1

Apply [L1] to NRn. There is a basis e1,,en of Rn and a basis a1e1,,arer of N, with nonzero a1ar.

step 1.1L1
3.1

The first isomorphism theorem and coordinatewise quotient give MRn/NR/(a1)R/(ar)Rnr. Any unit ai contributes the zero quotient and is removed; the remaining nonunit factors preserve the divisibility chain. This constructs the stated decomposition, including purely free, purely torsion, cyclic, and empty cases.

step 2.1givenalgebradischarge-construct

Depends on

Used by

Dependency tree · two levels

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Sources