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The Kazhdan–Lusztig inversion formula
Facts & Assumptions
Given: and the finite standard and Kazhdan–Lusztig bases of .
The chain-defined matrix is the two-sided inverse of , and the classical sign matrix gives (Inverse Kazhdan–Lusztig polynomials).
Bruhat intervals in are finite (Basic properties of the Bruhat order on ).
Statement
Let , and be the triangular matrices of Existence and uniqueness of the Kazhdan–Lusztig basis, Inverse Kazhdan–Lusztig polynomials and The -coefficient recursion, support, degree bounds and inversion. Then (a) , , and ; (b) , and the inversion formulas hold, i.e. and ; (c) for the dual basis from Inverse Kazhdan–Lusztig polynomials, . The inversion is proved from the bar-duality relations alone (no finite case check).
Proof
Bar-duality matrices. Entrywise bar applied to gives , because bar is an involution and is multiplicative on matrices over the commutative coefficient ring. The R theorem gives both and . Thus (a) holds.
The inverse matrix identity. By [F2], . From , inversion gives , since and . Applying entrywise bar yields . Its entry is ; triangular support restricts this finite sum to .
The signed inverse formula. Let be diagonal with , so . From [F2], ; from the R bar-symmetry, . Therefore , whose entry is . Triangular support again restricts to .
Dual-basis interpretation. Since is a basis of the finite free module , its coordinate functionals form the dual basis and satisfy . Put . Evaluating on gives ; because is invertible, , so . Conversely, if the dual evaluations are , the identity gives . This proves (c). All sums are finite by [F3], and no choice principle is used.
Remarks
The matrix inversion uses the locally proved basis/bar-duality clauses and the finite chain inverse with its sign convention. Coefficientwise positivity is not required.
Depends on
Used by
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