Alphabeta Math
TheoremStatement: AI-adaptedProof: Literature-sourcedprecheck passjudge pass (deepseek-v4-pro + claude-sonnet-5)audited 2026-08-17
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Kleisli composition is associative and unital

Statement

Let (T,η,μ) be a monad on C. For morphisms f:A→TB and g:B→TC, define

g⋆f:=μC∘T(g)∘f:A→TC.

Then ⋆ is associative, and ηA:A→TA is a two-sided identity at A.

Facts & Assumptions

Given: A monad (T,η,μ) as in Monad on a category and composable arrows f:A→TB, g:B→TC, and h:C→TD.

Proof

technique · direct
1.1given

Expanding the definitions gives (h⋆g)⋆f=μD∘T(μD)∘T2(h)∘T(g)∘f, while h⋆(g⋆f)=μD∘T(h)∘μC∘T(g)∘f.

2.1step 1.1given

Naturality of μ at h rewrites T(h)∘μC as μTD∘T2(h), and the monad associativity equation μD∘T(μD)=μD∘μTD identifies the two expansions in step 1.1.

3.1given∎

Naturality of η and the two distinct unit laws give f⋆ηA=μB∘T(f)∘ηA=μB∘ηTB∘f=f and ηB⋆f=μB∘T(ηB)∘f=f, so the asserted identities hold.

Depends on

Used by

Dependency tree · two levels

4 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources