Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-12
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The Turing-machine acceptance problem is computably enumerable complete

Statement

The language ATM of The Turing-machine acceptance problem ATM is c.e.-complete under computable many-one reductions.

Facts & Assumptions

Given: The acceptance language ATM.

[L1]

A language is c.e.-complete exactly when it is recognizable and every recognizable language many-one reduces to it, by Computably enumerable hardness and completeness under computable many-one reductions.

[L2]

The language ATM is recognizable, by The Turing-machine acceptance problem is recognizable.

[L3]

A coded pair M,w^ belongs to ATM exactly when the coded machine M accepts the word w, by The Turing-machine acceptance problem ATM.

Proof

technique · direct
1.1

By [L2], ATM is recognizable. To use [L1], it remains to prove c.e.-hardness.

L1L2given
1.2

Let L be any recognizable language, and choose a recognizer R for L. Define f(x):=R,x^. Because R is fixed, encoding its chosen code and pairing it with the canonical word-code of x is a total computable procedure. By [L3], xL exactly when R accepts x, and that happens exactly when f(x)ATM. Thus LmATM.

L3givenconstruct
2.1

Step 1.2 proves that every recognizable language many-one reduces to ATM, and step 1.1 already recorded recognizability. Therefore [L1] gives that ATM is c.e.-complete.

L1step 1.1step 1.2

Depends on

Used by

Dependency tree · two levels

13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources