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In dual bases, the matrix of is the transpose of the matrix of
Statement
Let be linear between finite-dimensional spaces, with ordered bases and . In the dual bases,
Facts & Assumptions
Given: The displayed map, bases, and their dual bases.
The transpose satisfies (The transpose or algebraic adjoint , , of a linear map ).
The dual families of the finite bases are bases of the dual spaces (The dual family of a finite basis is a basis of the dual space, with the same dimension).
The th column of a representing matrix is the coordinate column of the image of the th basis vector (Coordinate columns and matrices of linear maps relative to ordered bases).
The transpose of an matrix has entry equal to the original entry (The transpose of a matrix).
Proof
Write , so [L3] gives and therefore .
The entry of is the coefficient of in the expansion of along the dual basis . Since every satisfies , that coefficient is , which by [L1] equals .
By [L4], step 2.1 says exactly that the matrix of is the transpose of the matrix of . The calculation also covers or , where the matrices are empty rectangles.
Depends on
- The transpose or algebraic adjoint $T^*:W^*\to V^*$, $T^*(g)=g\circ T$, of a linear map $T:V\to W$
- The dual family of a finite basis is a basis of the dual space, with the same dimension
- Coordinate columns $[v]_{\mathcal B}$ and matrices $[T]_{\mathcal B}^{\mathcal C}$ of linear maps relative to ordered bases
- The transpose $A^{\mathsf T}$ of a matrix
Used by
Dependency tree · next 3 levels
Direct dependencies and their dependencies through the next three levels: 34 results over 11 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.
Sources
- H. Pinkham, Linear Algebra, Chapter 6 (standard reference, not scraped)