Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-05
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A bounded linear functional on an arbitrary subspace extends with the same norm, without assuming the subspace is closed

Statement

Let X be a normed space over R or C, let MX be a linear subspace, and let f0:MR or f0:MC be a bounded linear functional over the ambient scalar field. Then there exists a bounded linear extension F of f0 to all of X such that F=f0.

No closedness hypothesis on M is needed.

Facts & Assumptions

Given: A normed space X over R or C, a linear subspace MX, and a bounded linear functional f0 on M.

[L1]

In the real case, a bounded linear functional on a subspace extends with the same norm (A bounded real linear functional on a subspace of a real normed space extends with the same norm).

[L2]

In the complex case, a bounded linear functional on a subspace extends with the same norm (A bounded complex linear functional on a subspace of a complex normed space extends with the same norm).

[L3]

The page's normed-space language is read over either scalar field by the convention of Real and complex scalar conventions for normed spaces.

Proof

technique · direct
1.1

If the scalar field is R, then [L1] applies exactly as stated to the given subspace M and produces a norm-preserving extension of f0 to X.

L1L3given
1.2

If the scalar field is C, then [L2] applies exactly as stated to the given subspace M and produces a norm-preserving extension of f0 to X.

L2L3given
2.1

Neither step 1.1 nor step 1.2 uses or requires that M be closed; each cited theorem assumes only that M is a linear subspace. Therefore every bounded linear functional on an arbitrary subspace extends with the same norm.

step 1.1step 1.2L1L2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources