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TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-09-05
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One-sided Hardy-Littlewood inequalities for the Dini derivatives of a continuous monotone function

Statement

Let F:[a,b]→R be continuous and nondecreasing (Nondecreasing, increasing (strictly increasing), nonincreasing, decreasing, monotone and strictly monotone real functions on a subset of R, with the dictionary to monotone sequences). Let [u,v]⊆[a,b] with u<v.

  1. For every R>0, if ER+(u,v):={x∈[u,v):D+F(x)>R}, then R λ(ER+(u,v))≤F(v)−F(u).
  2. For every 0<r<R, if Er,R−(u,v):={x∈(u,v]:D−F(x)<r}, then (R−r) λ(Er,R−(u,v))≤R(v−u)−F(v)+F(u).

Here λ is Lebesgue measure from Lebesgue measurable sets, the family L(Rn), and the restricted set function λn.

Facts & Assumptions

Given: The continuous nondecreasing function F:[a,b]→R and the subinterval [u,v]⊆[a,b].

[A1]

The symbols are those of the statement.

Proof

technique · direct
1.1givenalgebra

Fix R>0 and put G(x):=F(x)−Rx on [u,v]. If x∈ER+(u,v), then some y∈(x,v] satisfies F(y)−F(x)y−x>R, hence G(y)>G(x). Therefore ER+(u,v) is contained in the rising-sun set of G on [u,v]. By Riesz's rising sun lemma with the correct endpoint conclusion, the components of that set are intervals In whose left and right endpoints we call cn,dn, with each In either [u,dn) or (cn,dn), and with G(cn)≤G(dn) for every n. Thus R(dn−cn)≤F(dn)−F(cn) for every n. Summing over finitely many components and using that the disjoint ordered intervals In lie in [u,v] gives R∑n≤N(dn−cn)≤∑n≤N(F(dn)−F(cn))≤F(v)−F(u), so R λ(ER+(u,v))≤F(v)−F(u).

2.1step 1.1algebra

Fix 0<r<R and put H(x):=Rx−F(x) on [u,v]. If x∈Er,R−(u,v), then for some y∈[u,x) one has F(x)−F(y)x−y<r, hence H(x)−H(y)>(R−r)(x−y)>0. Reflecting H across the midpoint of [u,v] turns this into the right-hand rising-sun situation on a continuous function, so the same argument as in step 1.1 yields a disjoint family of intervals whose total length bounds λ(Er,R−(u,v)) and on each such interval H(d)−H(c)≥(R−r)(d−c). Summing gives (R−r) λ(Er,R−(u,v))≤H(v)−H(u)=R(v−u)−F(v)+F(u).

3.1step 1.1step 2.1∎

Steps 1.1 and 2.1 are the two asserted inequalities.

Depends on

Used by

Dependency tree · two levels

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Sources