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TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-26
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Orbits on ordered pairs correspond to suborbits

Statement

Let G act transitively on Ω, and fix α∈Ω. Then the assignment G⋅(α,β)⟼Gα⋅β is a bijection from the G-orbits on Ω×Ω to the suborbits of the action at α.

Facts & Assumptions

Given: A transitive action of G on Ω and a point α∈Ω.

[L1]

A suborbit at α is an orbit of the stabilizer Gα on Ω (Rank, suborbits, and subdegrees of a transitive action).

[L2]

A transitive action sends any chosen point to any other point by some element of G (Left group actions, transitive actions, and faithful actions).

Proof

technique · direct
1.1L2choose

Every G-orbit on Ω×Ω contains some pair (α,β): for (x,y) choose g∈G with g⋅x=α by [L2], and then (g⋅x,g⋅y)=(α,g⋅y).

1.2L1choose

The assignment is well defined. If (α,β1) and (α,β2) lie in the same G-orbit, choose g∈G with g⋅(α,β1)=(α,β2). Then g∈Gα, so β2=g⋅β1 and the two second coordinates lie in the same suborbit.

1.3L1

The assignment is surjective because every suborbit has the form Gα⋅β, and it is the image of the orbital G⋅(α,β).

1.4L1choose

The assignment is injective. If Gα⋅β1=Gα⋅β2, choose g∈Gα with g⋅β1=β2. Then g⋅(α,β1)=(α,β2), so the two pairs lie in the same G-orbit.

2.1step 1.2step 1.3step 1.4∎

Steps 1.2, 1.3, and 1.4 show that orbital classes on ordered pairs correspond bijectively to suborbits at α.

Depends on

Used by

Dependency tree · two levels

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Sources