Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passaudited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Positive oriented atlases characterize orientations except for one-manifolds with boundary

Statement

Let M be an n-manifold with boundary. If n2, or if n>0 and M=, an orientation of the tangent determinant lines is equivalent to an atlas whose transition Jacobians are positive. Any such atlas determines an orientation for every n>0, but the converse can fail when n=1 and M. In dimension zero, arbitrary pointwise signs remain the governing formulation.

Facts & Assumptions

Given: A smooth n-manifold M with boundary.

[L1]

An orientation is a smooth choice of determinant ray, and for n>0 a chart is oriented when its coordinate frame lies in that ray (Oriented smooth manifolds and oriented charts).

[L2]

In positive dimension, determinant rays are equivalent to positive-basis classes (Orientations and positive basis classes agree in positive dimension).

[L3]

Boundary charts take values in Hn, and their last positive coordinate direction is inward at the face (Smooth charts, atlases, and structures with boundary; Inward, outward, and boundary-tangent vectors).

Proof

technique · direct
1.1

Suppose an orientation is selected and either n2, or n>0 and M=. By [L1] and [L2], each chart frame has a sign relative to that ray; continuity makes this sign locally constant, so restrict to its sign components. On a negative interior chart, reverse one coordinate. On a negative boundary chart with n2, reverse one of the first n1 coordinates; this preserves Hn while reversing the frame orientation. The resulting positive charts cover M.

givenL1L2L3constructalgebra
2.1

On overlaps, [L2] says that both coordinate frames are positive precisely when their change determinant is positive. Thus step 1.1 gives a positive-transition atlas. Conversely, in every n>0, positive transition determinants make the chart-frame rays agree on overlaps and hence define the orientation of [L1].

givenL1L2step 1.1
3.1

The converse in step 2.1 is not reversible for an arbitrary orientation when n=1 and there is boundary: by [L3], a positive boundary chart necessarily declares the inward vector positive. On the standard oriented interval [0,1], +x is inward at 0 but outward at 1, so its orientation cannot be represented by positive boundary charts at both endpoints. Finally, when n=0, [L1] shows why independent pointwise signs, rather than the unique empty chart frame, remain the correct datum.

givenL1L3step 2.1algebra

Depends on

Used by

Dependency tree · two levels

11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources