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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
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Pullback induces a well defined map on de rham cohomology
Statement
For a smooth , the formula defines a linear map for every integer .
Facts & Assumptions
Given: A smooth and a closed -form on .
De rham cohomology: The real de Rham cohomology is , with as in def-closed-and-exact-differential-forms. This is def-cohomology-object-of-a-cochain-complex in real vector spaces. Only a closed form represents a class . For closed forms , equality means precisely for some -form . Addition and real scalar multiplication are induced by those of forms. All groups on the empty manifold are zero.
Pullback is a morphism of de rham complexes: A smooth map induces a degree-zero real cochain map .
A chain map induces a well-defined map on homology: Let be a chain map. For every there is a unique morphism such that the quotient maps from cycles to homology commute with .
Proof
The cochain identity gives . If , then , so both representatives produce the same class.
Reindex by and , with unchanged differentials. The cochain identity is the chain-map identity; its cycles and boundaries at are exactly and . The induced-homology theorem therefore gives the displayed linear map, agreeing with step 1.1 by its quotient property.
Source locator
Lee, Introduction to Smooth Manifolds, 2nd ed., Chapter 17, pp.441–443, Proposition 17.2 and Corollary 17.3; local quotient calculations below.
Depends on
Used by
Dependency tree · two levels
11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- John M. Lee, Introduction to Smooth Manifolds, second edition (standard reference, not scraped)