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General adversary bound characterizes Boolean quantum query complexity

Statement

For every finite partial Boolean function f:D→{0,1}, bounded-error quantum query complexity at error at most 1/3 satisfies Q1/3(f)=Θ(Adv⁡±(f)). For nonconstant f, the lower coefficient is 1/2−2/3 and the reflection evaluator gives an upper bound below 2048Adv⁡±(f). For constant f both quantities are zero.

Facts & Assumptions

Given: A finite partial Boolean function with the standard XOR query model.

[F1]

General adversary spectral lower bound for quantum queries: Q_ε(f)≥(1/2−√(ε(1−ε)))Adv±(f).

[F2]

Boolean-output filtered γ₂ equals the general adversary value: for nonconstant finite partial Boolean functions, the Boolean filtered factorization value is exactly Adv±.

[F3]

Dual reflection evaluator query complexity: a supplied balanced dual certificate of cost A≥1 gives an evaluator using fewer than 2048A queries.

[F4]

Quantum query complexity: the general query-cost coordinate is the worst-case number of designated oracle calls, excluding nonoracle gates.

[F5]

Dual vector formulation of the general adversary bound: for nonconstant f the certificate minimum equals Adv± and is attained.

[F7]

Finite Boolean query problem and error model for adversary bounds: Q1/3(f) is the least worst-case standard XOR query count for success probability at least 2/3 on every promised input.

[F8]

General adversary matrix and spectral bound: for constant f, Adv±(f) is defined to be zero.

[F9]

Dual reflection evaluator has bounded-error correctness: for every supplied finite dual certificate with class costs at most A≥1, the reflection evaluator outputs f(x) with probability at least 2/3 on every promised input x.

Proof

1.1givenF1F7algebra

If f is nonconstant, apply [F1] with ε=1/3 to obtain Q_{1/3}(f)≥(1/2−√2/3)Adv±(f), whose coefficient is positive.

1.2givenF2F3F5F6F7F9algebra

Still assuming f is nonconstant, [F2] identifies the Boolean filtered factorization value with Adv±(f). By [F5] the dual certificate optimum is attained with cost A=Adv±(f); reciprocal rescaling balances C_0,C_1 without increasing their maximum. By [F6], A≥1. For this certificate and bound A, [F9] gives success probability at least 2/3 on every promised input, while [F3] bounds the same evaluator's query count by fewer than 2048A. It therefore qualifies in the minimization [F7], giving Q_{1/3}(f)<2048Adv±(f).

2.1givenF4F7F8step 1.1step 1.2∎

If f is constant, the algorithm that outputs its fixed value without queries computes it exactly, so Q_{1/3}(f)=0 by [F7]. By [F8], Adv±(f)=0 as well. Combining this case with steps 1.1–1.2 proves the claimed uniform constant-factor bounds at error at most 1/3. Nonoracle gates are excluded from query cost by [F4].

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