Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Finite abelian Parseval identity

Statement

For f,g:G→C, ∑χ∈G^(FGf)(χ)(FGg)(χ)‾=∑x∈Gf(x)g(x)‾. For a finite set X, the counting inner product on CX is ⟨f,g⟩X:=∑x∈Xf(x)g(x)‾; it is linear in the first argument. The displayed identity says this inner product is preserved.

Facts & Assumptions

Given: A finite abelian group G and functions f,g:G→C.

[F1]

The transform matrix U satisfies U∗U=IG (Finite abelian Fourier transform is unitary).

[F2]

The transform is represented by the matrix entries Uχ,x=NR−1/2χ(x)‾ (Normalized Fourier transform on a finite abelian group).

Proof

1.1F1F2algebra

Expanding the left side in point-mass coordinates using [F2] gives ∑χ(∑xUχ,xf(x))(∑yUχ,yg(y))‾=∑x,yf(x)g(y)‾(∑χUχ,xUχ,y‾). The inner finite sum is the conjugate of the (x,y) entry of U∗U, so [F1] makes it 1 if x=y and 0 otherwise.

2.1step 1.1∎

The diagonal terms remaining from step 1.1 are exactly ∑xf(x)g(x)‾. Taking g=f gives preservation of the squared counting norm as well.

Depends on

Used by

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Sources