Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
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Teleportation Pauli correction identity

Statement

For every qubit vector ∣ψ⟩ and bits a,b∈{0,1}, the teleportation branch byproduct is XbZa∣ψ⟩, and the prescribed correction returns it exactly:

ZaXbXbZa∣ψ⟩=∣ψ⟩.

The operator order is part of the statement; no Pauli factors are commuted.

Facts & Assumptions

Given: a,b∈{0,1} and a qubit vector ∣ψ⟩.

[A1]

a and b are bits.

[F1]

Teleportation Bell-basis expansion gives the branch byproduct XbZa∣ψ⟩.

[F2]

The Pauli matrices defines X=(0110) and Z=(100−1).

Proof

1.1givenA1F2algebra

From the matrices in [F2], direct multiplication gives X2=I and Z2=I. Therefore XbXb=I and ZaZa=I for the two possible values of each bit.

2.1step 1.1algebra

Keeping the operator order fixed, ZaXbXbZa=Za(XbXb)Za=ZaIZa=ZaZa=I by step 1.1. This also covers a=b=1 without using an anticommutation swap.

3.1step 2.1F1algebra∎

Applying the identity in step 2.1 to the byproduct vector from [F1] yields ZaXb(XbZa∣ψ⟩)=∣ψ⟩ for every qubit vector.

Depends on

Used by

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources