Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-02
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Redei's theorem: every nonempty tournament has a directed Hamilton path

Statement

Every nonempty finite tournament has a directed path containing every vertex exactly once.

Facts & Assumptions

Given: A nonempty finite tournament T.

[F1]

Between each pair of distinct tournament vertices exactly one of the two possible arcs occurs (A tournament is an orientation of a complete finite graph).

[F2]

A directed path follows each displayed arc and has no repeated vertex (Directed walks, trails, paths and cycles, and strong connectivity).

[L1]

Induction proves a statement for every natural number from a base case and an induction step (The principle of mathematical induction).

Proof

technique · induction on $n=|V(T)|$
1.1

If n=1, the one-vertex directed path contains every vertex.

F2base
1.2

Assume every tournament on n−1 vertices has a directed Hamilton path, where n>1. Remove a vertex x. The remaining tournament has, by the induction hypothesis, a directed Hamilton path v1,v2,…,vn−1.

F1ih
2.1

If xv1 is an arc, prepend x. If no arc xvj exists, [F1] gives vjx for every j, so append x. Otherwise let j be the least index with arc xvj; then j>1 and minimality plus [F1] gives the arc vj−1x. Insert x between vj−1 and vj.

step 1.2F1cases
3.1

In every case the resulting list follows directed arcs and contains each vertex of T exactly once, so it is a directed Hamilton path.

step 1.2step 2.1F2
4.1

The base case and induction step prove Redei's theorem for every nonempty finite tournament.

step 1.1step 1.2step 3.1L1discharge-induction∎

Depends on

Used by

Dependency tree · two levels

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Sources