Alphabeta Math
TheoremStatement: Literature-sourcedProof: Literature-sourcedprecheck passaudited 2026-08-13
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The Schreier refinement theorem

Statement

Any two finite subnormal series of a group have equivalent refinements (Subnormal and normal series, factors, refinements, and equivalence).

Facts & Assumptions

Given: Subnormal series G=G0⊵⋯⊵Gm=1 and G=H0⊵⋯⊵Hn=1.

[F1]

A refinement inserts subgroup terms, and two series are equivalent when their nontrivial factors can be paired up to isomorphism after repetitions are deleted (Subnormal and normal series, factors, refinements, and equivalence).

[L1]

For A⊴A∗ and B⊴B∗, the butterfly constructions give normal adjacent terms and isomorphic quotient factors (The Zassenhaus butterfly lemma).

Proof

technique · direct
1.1

For 0≤i<m and 0≤j≤n, set Gi,j:=Gi+1(Gi∩Hj). Then Gi,0=Gi and Gi,n=Gi+1; [L1] applied to Gi+1⊴Gi and Hj+1⊴Hj gives Gi,j+1⊴Gi,j.

givenL1
1.2

For 0≤j<n and 0≤i≤m, set Hj,i:=(Gi∩Hj)Hj+1. Concatenating these chains gives a subnormal refinement of the H-series.

givenL1F1
2.1

Concatenating the finite chains Gi,0⊵⋯⊵Gi,n over i=0,…,m−1 yields a subnormal refinement of the G-series, possibly with repeated adjacent terms.

step 1.1F1
2.2

For every cell (i,j), [L1] identifies Gi,j/Gi,j+1 with Hj,i/Hj,i+1. Thus the two refinements have their mn displayed factors paired by (i,j)↔(j,i).

step 1.1step 1.2L1
3.1

Deleting repeated adjacent terms deletes exactly the trivial factors on both sides of each paired cell, so the remaining factors are still paired and isomorphic; the refinements are equivalent.

step 2.1step 2.2F1∎

Depends on

Used by

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources