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DARE structure-preserving doubling converges with a quantified quadratic error envelope

Statement

Under the discrete stabilizability and detectability hypotheses of Stabilizability and detectability give the unique stabilizing positive-semidefinite DARE solution, start the exact recurrence of Finite-budget structure-preserving doubling iteration for the DARE from A0=A, G0=BR−1B∗, and H0=Q. Then all inverses exist, Gj,Hj⪰0, and Hj converges to the stabilizing DARE solution X∗. More quantitatively, there are q∈(0,1), an index j0, and C>0 such that ∥Hj−X∗∥F,W−1≤Cq2j+1(j≥j0), where W≻0 is a Stein witness constructed from the closed-loop matrix. The envelope ϵj=Cq2j+1 obeys ϵj+1=ϵj2/C. The constants are conditional on the closed-loop spectral separation and its norm conditioning; no uniform constant depending only on dimension is asserted.

Facts & Assumptions

Given: The standard DARE data and the exact discrete stabilizability/detectability hypotheses.

[F1]

Stabilizability and detectability give the unique stabilizing positive-semidefinite DARE solution: the finite-horizon iterates P0=0, Pk+1=f(Pk) increase to X∗, and Ac(X∗) is Schur stable.

[F2]

The DARE doubling recurrence composes two Riccati steps and preserves positive semidefiniteness: the recurrence is well-defined, preserves Gj,Hj⪰0, and Hj=f2j(0).

[F3]

Powers of a Schur-stable matrix decay geometrically up to a polynomial factor: powers of every Schur-stable matrix have a geometric bound with any rate above its spectral radius.

[F4]

A non-negative operator has a unique non-negative square root: a positive-semidefinite matrix has a positive-semidefinite square root; for W≻0 this square root is positive definite.

[F5]

Proof

1.1F1F2algebra

By [F2], Hj=P2j and Gj,Hj remain positive semidefinite. Since [F1] gives Pk→X∗, the subsequence Hj=P2j also converges to X∗. No inverse of A is used.

1.2F1F3F4algebra

Put M=Ac(X∗). By [F1], M is Schur stable; [F3] therefore makes W=∑k=0∞(M∗)kMk converge in norm. It is positive definite, W⪰I, and M∗WM=W−I. If w=∥W∥2, then v∗M∗WMv≤(1−w−1)v∗Wv, so the induced W-norm ∥M∥W:=∥W1/2MW−1/2∥2 is at most q0=1−w−1<1. Choose q with q0<q<1. Since Pk→X∗ and Ac(Pk) is continuous on Pk⪰0, choose k0 so ∥Ac(Pk)∥W≤q for all k≥k0.

2.1F1F5step 1.2algebrainduction∎

Let Ek=X∗−Pk⪰0. The Riccati-map difference identity in [F1] gives Ek+1=M∗EkAc(Pk). Define ∥E∥F,W−1=∥W−1/2EW−1/2∥F. By [F5], for k≥k0, ∥Ek+1∥F,W−1≤∥M∥W∥Ac(Pk)∥W∥Ek∥F,W−1≤q2∥Ek∥F,W−1. Iteration gives ∥Ek∥F,W−1≤∥Ek0∥F,W−1q2(k−k0). Taking k=2j and setting C=max⁡{1,∥Ek0∥F,W−1q−2k0} proves the displayed envelope for all 2j≥k0. Since C>0, direct calculation gives ϵj+1=Cq2j+2=ϵj2/C.

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