Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-02
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Second isomorphism theorem for rings: S/(S∩I)≅(S+I)/I

Statement

Second isomorphism theorem for rings: S/(S∩I)≅(S+I)/I.

If S is a unital subring of R and I⊴R, then this is an isomorphism of unital rings.

Facts & Assumptions

Given: A unital subring S⊆R and a two-sided ideal I⊴R.

[L2]

The first ring isomorphism theorem identifies a ring modulo a kernel with its image (First isomorphism theorem for rings: R/ker⁡f≅im⁡f).

[L3]

The canonical quotient map is a surjective ring homomorphism (The canonical projection R→R/I is a surjective ring homomorphism with kernel I).

Proof

technique · direct
1.1

Restrict the quotient map S+I→(S+I)/I to ϕ:S→(S+I)/I, ϕ(s)=s+I.

L1L2L3givenconstruct
2.1

Its kernel is S∩I, and every (s+i)+I equals s+I, so its image is all of (S+I)/I.

step 1.1L1L2L3givenalgebra
3.1

The kernel and image computation gives S/(S∩I)≅(S+I)/I.

step 2.1∎

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

16 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources