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Sectional size discretization separates grid and cutoff errors

Statement

Let μt be a continuous solution on [0,T] with initial mass M1, and let νtR be the retained measure of the finite sectional system initialized by retaining the projection PΔμ0 on pivots at most R and placing the projected tail mass ∫(R,∞)x PΔμ0(dx) in its reported reservoir. Assume R is a pivot endpoint and Δ≤1. Then dBL(νtR,μt)≤eCTt[CQTΔ+Δ2M0(μt)+M1R+2K∗M12taR],0≤t≤T, where CQ is from Fixed-pivot projection has first-order bounded-Lipschitz kernel quadrature error, CT is a finite bounded-number stability constant, and the terms proportional to Δ, R−1 are respectively the grid and cutoff errors. The reservoir itself is diagnostic and does not recreate the omitted transition law.

Facts & Assumptions

Given: The continuous weak model, the finite reported-overflow scheme, and the no-cutoff pivot comparison.

[F1]

Continuous-size coagulation-fragmentation weak model: the continuous population satisfies the weak coagulation-fragmentation equation.

[F2]

Conservative fixed-pivot redistribution on a finite positive grid: in-range sizes are redistributed by positive barycentric weights and above-cutoff products enter a mass reservoir.

[F3]

Finite sectional coagulation-fragmentation balance with reported overflow: the finite algorithm applies the in-range pivot rule and omits retained particles for products above R.

[F4]

Bounded-kernel measure solutions conserve mass and control number and second moments: M1 is constant and M0 is bounded on [0,T].

[F5]

The unbounded fixed-pivot flow has first-order grid error: the unbounded-pivot flow differs from μt by at most eCTtCQTΔ+(Δ/2)M0(μt).

[F6]

Finite cutoff differs from the unbounded pivot model by a controlled return error: replacing the unbounded-pivot flow by the finite reported-overflow flow adds at most eCTt[M1/R+2K∗M12t/(aR)].

Proof

1.1givenF1F2F3

By [F1] the target is a continuous-model solution; [F2]–[F3] specify that finite products above R leave the retained measure and enter only the diagnostic reservoir. Form the unbounded-pivot solution ηt from the initial projection PΔμ0. Split the difference as dBL(νtR,μt)≤dBL(νtR,ηt)+dBL(ηt,μt). This is the triangle inequality for the discrepancy in [F1].

2.1givenF4F5F6step 1.1algebra∎

Apply [F5] to the second term and [F6] to the first term. Their stated bounds use the same conserved initial mass M1 and finite-horizon number bound, so taking a common stability constant CT and adding gives exactly the displayed estimate. The first two contributions vanish with grid spacing, and the last two with cutoff growth.

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