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TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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Smith normal form is unique through the gcds of its minors

Statement

Smith normal form is unique and its entries are recovered from successive determinantal divisors. If a matrix has nonzero Smith entries d1dr, then, up to associates,

Δk=d1dk(0kr),Δk=0(k>r),

and dk is the successive quotient Δk/Δk1.

Facts & Assumptions

Given: Determinantal ideals and divisors from Determinantal divisors from the minors of a matrix over a PID, including D0=R; determinant multilinearity and alternation (The determinant is the unique normalized alternating multilinear function on the columns).

[L1]

Every rectangular matrix over a PID is equivalent to a Smith diagonal matrix (Every matrix over a PID has a Smith normal form).

Proof

technique · direct
1.1

Every k-minor of PA is an R-linear combination of k-minors of A by determinant multilinearity, so Dk(PA)Dk(A); applying the same argument to P1 gives equality. Right multiplication is identical. Thus equivalent matrices have the same determinantal ideals.

givenalgebra
1.2

For a Smith diagonal matrix with d1dr, every nonzero k-minor is a product of k diagonal entries and is divisible by d1dk, while the leading k-minor equals that product. Hence Δk is associate to d1dk for kr and is 0 for k>r.

L1algebra
2.1

Step 1.1 makes the Δk invariants of equivalence. Step 1.2 recovers r as the last nonzero index and recovers each dk up to a unit from successive products, proving uniqueness. It includes k=0, zero matrices, one-by-one matrices, and all rectangular ranks.

step 1.1step 1.2

Depends on

Used by

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