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Smith normal form is unique through the gcds of its minors
Statement
Smith normal form is unique and its entries are recovered from successive determinantal divisors. If a matrix has nonzero Smith entries , then, up to associates,
and is the successive quotient .
Facts & Assumptions
Given: Determinantal ideals and divisors from Determinantal divisors from the minors of a matrix over a PID, including ; determinant multilinearity and alternation (The determinant is the unique normalized alternating multilinear function on the columns).
Every rectangular matrix over a PID is equivalent to a Smith diagonal matrix (Every matrix over a PID has a Smith normal form).
Proof
Every -minor of is an -linear combination of -minors of by determinant multilinearity, so ; applying the same argument to gives equality. Right multiplication is identical. Thus equivalent matrices have the same determinantal ideals.
For a Smith diagonal matrix with , every nonzero -minor is a product of diagonal entries and is divisible by , while the leading -minor equals that product. Hence is associate to for and is for .
Step 1.1 makes the invariants of equivalence. Step 1.2 recovers as the last nonzero index and recovers each up to a unit from successive products, proving uniqueness. It includes , zero matrices, one-by-one matrices, and all rectangular ranks.
Depends on
Used by
Dependency tree · two levels
13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- M. Brussel, Finitely Generated Modules over a PID, Theorem 2.1.6 (standard reference, not scraped)
- A. Apisa, Wisconsin Math 542, Theorem 27 (standard reference, not scraped)