Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-06
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A submodule of an arbitrary-rank free module over a PID is free

Statement

Assume the Axiom of Choice. If R is a PID, F is a free R-module, and NF, then N is free (with no finite-rank assumption on F).

Proof

Given: a basis of F, a submodule NF, and the Axiom of Choice. By the well-ordering theorem, index the basis as (eα)α<κ.

1.1

Put Fα=eβ:β<α and Nα=NFα. The image of Nα+1 in Fα+1/FαR is an ideal Iα of R, hence is either zero or free of rank one. Thus 0NαNα+1Iα0 splits.

givenalgebra
2.1

At each successor with Iα0, choose a generator and a lift xαNα+1; the splitting gives Nα+1=NαRxα. At a limit λ, every element has finite support, so Nλ=α<λNα and the nested union of the earlier bases is a basis. Transfinite induction through the terminal stage κ therefore gives a basis of Nκ=N. For κ=0, this is the empty basis of N=0.

step 1.1construct

Depends on

Used by

Dependency tree · two levels

17 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources