Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-01
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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The braid group surjects onto the symmetric group

Statement

For every n2, the assignment σi(i i+1) extends to a surjective homomorphism

πn:BnSn.

Facts & Assumptions

Given: The Artin presentation of Bn and the adjacent transpositions in Sn.

[L1]

The braid group Bn has generators σ1,,σn1 with the Artin braid and distant-commutativity relations (The braid group by Artin presentation).

[L3]

The symmetric group satisfies the Coxeter relations for adjacent transpositions (The symmetric group has the Coxeter presentation).

[L4]

A map of generators satisfying the relators extends uniquely from a presented group (Von Dyck's theorem: maps of generators that satisfy the relators extend uniquely from a presented group).

Proof

technique · direct
1.1

By [L3], the adjacent transpositions in Sn satisfy the braid relations and the distant-commutativity relations from [L1]. Therefore [L4] extends the assignment σi(i i+1) to a homomorphism πn:BnSn.

L1L3L4givenconstruct
2.1

The image of πn contains every adjacent transposition, so [L2] makes πn surjective.

L2step 1.1

Depends on

Used by

Dependency tree · two levels

18 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources