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TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-05
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The lozenge and compact-square forms of enriched naturality are equivalent

Statement

Let T,S:A→B be V-functors and let αA:1→B(TA,SA) be a family of components. Then the lozenge equation of Enriched natural transformation is equivalent to the commutativity, for every A,B, of the square

A(A,B)→TA,BB(TA,TB)↓SA,B↓B(1,αB)B(SA,SB)→B(αA,1)B(TA,SB),

where B(1,αB) and B(αA,1) are the canonical maps induced by composition with the components of α.

Facts & Assumptions

Given: V-functors T,S:A→B and a family αA:1→B(TA,SA).

[L1]

A V-natural transformation is exactly such a family satisfying the lozenge equation against every hom-object (Enriched natural transformation).

Proof

technique · direct
1.1L1given

By [L1], the lozenge compares two composites from A(A,B) to B(TA,SB) obtained by first applying SA,B or TA,B and then composing with the component of α at the source or target. The canonical maps B(αA,1) and B(1,αB) are precisely those postcomposition and precomposition maps written without the unitors.

2.1L1step 1.1algebra

After identifying 1⊗A(A,B) and A(A,B)⊗1 with A(A,B) by the unitors, the two composites in the lozenge become exactly B(αA,1)∘SA,B and B(1,αB)∘TA,B. Hence the lozenge equation holds if and only if those two morphisms are equal, which is exactly the commutativity of the displayed square.

3.1step 2.1∎

Therefore the lozenge and compact-square formulations are equivalent.

Depends on

Used by

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Sources