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TheoremStatement: AI-adaptedProof: Literature-sourcedprecheck passjudge pass (deepseek-v4-pro + claude-sonnet-5)audited 2026-08-17
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The comparison functor to the Eilenberg–Moore category exists and is unique

Statement

Let F:C⇄D:U be an adjunction with counit ε inducing a fixed monad T on C on the nose, and write FT⊣UT for the Eilenberg–Moore adjunction with counit εT. There is exactly one functor K:D→CT satisfying

UTK=U,KF=FT,K(εd)=εKdT for every object d,

namely the comparison functor

K(d)=(Ud,Uεd),K(h)=U(h).

These three equalities are what it means for K to be a morphism of adjunctions from F⊣U to the Eilenberg–Moore adjunction.

Facts & Assumptions

Given: An adjunction F⊣U with unit η and counit ε as in Adjunction by unit, counit, and the triangle identities, inducing T=UF and μ=UεF as in Every adjunction induces a monad on the domain of its left adjoint, together with the Eilenberg–Moore adjunction of The free–forgetful Eilenberg–Moore adjunction induces the given monad.

Proof

technique · direct
1.1given

For d∈D set K(d)=(Ud,Uεd), and for h:d→d′ set K(h)=Uh.

2.1step 1.1given

The triangle identity gives Uεd∘ηUd=1Ud. Naturality of ε at εd gives the algebra associativity equation for Uεd, and naturality at h gives Uh∘Uεd=Uεd′∘T(Uh); hence the objects and arrows in step 1.1 are algebras and algebra homomorphisms.

3.1step 1.1step 2.1∎

Directly UTK=U, and KFA=(UFA,UεFA)=(TA,μA)=FTA; the Eilenberg–Moore counit at K(d) is Uεd, so the counit data also agree. These strict equalities force the underlying arrow action and every structure map, proving uniqueness.

Depends on

Used by

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Sources