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TheoremStatement: Literature-sourcedProof: Literature-sourcedprecheck passaudited 2026-08-17
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The Kleisli adjunction induces the given monad

Statement

For a monad (T,η,μ) on C, there is an adjunction

FT:C⇄CT:UT

whose induced monad is (T,η,μ) on the nose.

Facts & Assumptions

Given: The Kleisli category CT of Kleisli category of a monad and the monad (T,η,μ) used to define it.

Proof

technique · direct
1.1given

Define FTA=A and FT(f)=ηB∘f:A→TB. Define UTA=TA, and for a Kleisli arrow g:A→TB put UT(g)=μB∘T(g):TA→TB.

2.1step 1.1given

The Kleisli identity and associativity laws show that both assignments preserve identities and composition. Moreover CT(FTA,B)=C(A,TB)=C(A,UTB) naturally in A and B, so they form an adjunction.

3.1step 1.1step 2.1∎

The unit is η. The counit at a Kleisli object B is represented by 1TB:TB→TB, and applying UT gives μB; the Kleisli unit laws are the triangle identities. Thus UTFT=T and the induced unit and multiplication are η and μ.

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources