Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
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Algebraicity is transitive in towers of field extensions

Statement

If F⊆K⊆L, the extension K/F is algebraic, and L/K is algebraic, then L/F is algebraic.

Facts & Assumptions

Given: A tower F⊆K⊆L with K/F and L/K algebraic, and an element a∈L.

[L1]

Finitely many algebraic generators produce a finite extension (An extension generated by finitely many algebraic elements is finite).

[L2]

An algebraic element generates a finite simple extension (An element is algebraic over F if and only if its simple extension F(a)/F is finite).

[L4]

Every finite extension is algebraic (Every finite field extension is algebraic).

[L5]

Algebraicity means satisfying a nonzero polynomial over the base (Algebraic and transcendental elements and algebraic extensions).

Proof

technique · direct
1.1givenL5choose

Since a is algebraic over K, choose a nonzero polynomial c0+c1t+⋯+cdtd∈K[t] with value zero at a.

2.1givenstep 1.1L1

Every coefficient ci is algebraic over F. Hence M=F(c0,…,cd) is finite over F by [L1].

3.1step 1.1step 2.1L2L3

The same polynomial lies in M[t], so a is algebraic over M and [L2] makes M(a)/M finite. The tower law [L3] makes M(a)/F finite.

4.1step 3.1L4∎

By [L4], a is algebraic over F. Since a was arbitrary, L/F is algebraic.

Depends on

Used by

Dependency tree · two levels

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Sources