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Unique normal subpair below a Brauer pair
Statement
If is a local Brauer pair and , exactly one block of satisfies .
Facts & Assumptions
Given: A local pair and a normal subgroup .
Normal inclusion requires a -stable block with relative Brauer product . (Normal inclusion of Brauer pairs)
Non-singleton block orbits have zero relative Brauer image. (Brauer maps kill nontrivial idempotent orbit sums)
The relative Brauer map is a unital surjective algebra homomorphism on its fixed-algebra domain. (Relative Brauer homomorphism)
Proof
Partition the primitive central block decomposition of in into its -orbits. The non-singleton orbit sums map to zero. The remaining blocks are individually -stable. Their relative images are orthogonal central idempotents whose sum is one: multiplicativity preserves idempotence and orthogonality. For centrality, lift an arbitrary target element through the surjective relative map; its lift commutes with each central source block, so their images commute.
Multiply this sum by primitive central . Each product is either or , since a nontrivial product would split ; at least one equals because the sum of products is , and at most one can equal by orthogonality. Its preimage block is -stable and satisfies the required equation. Every normal subpair must be one of these -stable blocks by [F1], proving uniqueness as well as existence.
Sources
Jacobsen, Block fusion systems and the center of the group ring, §§1.1 and 2.2, pp.3–8 and 13–18. Local argument and conventions as displayed above.
Depends on
Used by
Dependency tree · two levels
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Sources
- Jacobsen, Block fusion systems and the center of the group ring, §§1.1 and 2.2, pp.3–8 and 13–18 (standard reference, not scraped)